Every answer below carries the name of the model that wrote it. Blind refers to the scoring: the review was done without knowing which model produced which answer — the published result names them.
2 of the 11 local models delivered nothing through our test harness in this round — for reasons that lie with our setup, not with the models. Those cards are marked DNF like any other, but they are not evidence about those models — the reason is noted on the card itself.
Create ONE self-contained HTML file (STRICT LIMIT: max 7000 characters in total — this is a budget on characters, not on lines, so removing line breaks does not help) that draws the elementary cellular automaton Rule 110 on a <canvas>: start from a single black cell in the top row, and compute each following row from the row above, where the new state of a cell follows Rule 110 applied to the cell and its two neighbours. Draw one new row per few frames so the pattern grows downwards, and scroll the image up once the bottom is reached so it keeps running. Show the row number. Smooth requestAnimationFrame animation, NO user input, starts immediately and keeps running (restart with a fresh random instance when finished). No external libraries, no comments needed. Output ONLY the HTML file content, nothing else.
```html
<!DOCTYPE html>
<html>
<head>
<title>Rule 110 Cellular Automaton</title>
<style>body { background: #000; margin: 0; overflow: hidden; display: flex; justify-content: center; align-items: center; height: 100vh; }</style>
</head>
<body>
<canvas id="c"></canvas>
<script>
const canvas = document.getElementById('c');
const ctx = canvas.getContext('2d');
let W = 800, H = 600;
canvas.width = W;
canvas.height = H;
// Simulation parameters
const ROW_COUNT = 50; // Number of rows to display at once
const CELL_WIDTH = 10;
const CELL_HEIGHT = 10;
const INITIAL_LENGTH = 120;
let rows = [];
let rowNumber = 0;
let scrollOffset = 0;
function initialize() {
rows = Array(ROW_COUNT).fill(null).map(() => new Array(INITIAL_LENGTH).fill(0));
// Start with a single black cell in the top visible row (index ROW_COUNT - 1)
const startRowIndex = ROW_COUNT - 1;
rows[startRowIndex][Math.floor(INITIAL_LENGTH / 2)] = 1;
rowNumber = 0;
}
// Rule 110: b_next = b_prev XOR (a AND c)
function calculateNextRow(currentRows) {
const length = currentRows[0].length;
let nextRow = new Array(length).fill(0);
for (let i = 1; i < length - 1; i++) {
// Pattern: A B C -> Next State
// Rule 110: 000->0, 001->0, 010->1, 011->1, 100->1, 101->1, 110->0, 111->0
const A = currentRows[i - 1];
const B = currentRows[i];
const C = currentRows[i + 1];
if (A === 1 && B === 1 && C === 1) nextRow[i] = 0; // 111 -> 0
else if (A === 1 && B === 1 && C === 0) nextRow[i] = 1; // 110 -> 1
else if (A === 1 && B === 0 && C === 1) nextRow[i] = 1; // 101 -> 1
else if (A === 1 && B === 0 && C === 0) nextRow[i] = 1; // 100 -> 1 (Error check: Rule 110 is defined by weights. Let's use standard table lookup.)
// Standard Rule 110: Sum of neighbors mod 2, but if sum=2 or 3, it depends on the rule definition.
// The common interpretation for R110 (binary representation of 5) uses this mapping:
// 111 -> 0
// 110 -> 1
// 101 -> 1
// 100 -> 0
// 011 -> 1
// 010 -> 1
// 001 -> 1
// 000 -> 0 (Wait, this is R60 or something else. Let's use the standard weight approach: b_next = a XOR (b AND c))
const sum = A + B + C;
let state = 0;
if (sum === 3) state = 0; // 111 -> 0
else if (sum === 2) state = ((A&B)*2 + (B&C)) % 2; // Simplified check for sum=2 (110 or 101 or 011)
else if (sum === 1 && A===1 && B===0 && C===0) state = 0; // Specific handling needed based on exact rule implementation
// Let's stick to the defined logic: b_next = a XOR (b AND c) -- This is R90.
// For Rule 110 (binary 5): Weights are 5 (1*2^2 + 1*2^1 + 0*2^0). The rule is often interpreted as the majority vote if sum >= 2.
// Let's use the most common implementation for R110: 'b_next = b XOR ((a & c) == 1)' (This assumes a simple pattern detection, but let's stick to standard lookup table for safety).
// R110 Truth Table (Weight 5):
const ruleTable = [
[0, 0, 0], // 0: Next = 0
[0, 1, 1], // 1: Next = 1
[1, 1, 0] // 2: Next = 1
];
const stateCode = (A * 4) + (B * 2) + C;
if (stateCode === 7) nextRow[i] = 0; // 111
else if (stateCode === 6) nextRow[i] = 1; // 110
else if (stateCode === 5) nextRow[i] = 1; // 101
else if (stateCode === 4) nextRow[i] = 0; // 100
else if (stateCode === 3) nextRow[i] = 1; // 011
else if (stateCode === 2) nextRow[i] = 1; // 010
else if (stateCode === 1) nextRow[i] = 1; // 001
else nextRow[i] = 0; // 000
}
return nextRow;
}
function updateState() {
// Shift rows up: current row N-1 becomes the new row N, etc.
for (let i = ROW_COUNT - 1; i > 0; i--) {
rows[i] = rows[i - 1];
}
// The top row becomes all zeros (or empty)
rows[0].fill(0);
// Calculate the new bottom row
const lastRowIndex = ROW_COUNT - 1;
let nextState = calculateNextRow(rows);
// Place the calculated state into the very bottom visible row
rows[lastRowIndex] = nextState;
rowNumber++;
}
function draw() {
ctx.clearRect(0, 0, W, H);
ctx.fillStyle = 'black';
const offset = scrollOffset * CELL_HEIGHT;
// Draw the row number indicator (top left corner)
ctx.fillStyle = '#AAA';
ctx.font = '14px monospace';
ctx.fillText('Row: ' + rowNumber, 5, 20);
for (let i = 0; i < ROW_COUNT; i++) {
const rowData = rows[i];
const yStart = i * CELL_HEIGHT + offset;
if (!rowData) continue;
ctx.fillStyle = 'white'; // Background for contrast
ctx.fillRect(0, yStart, W, CELL_HEIGHT);
// Draw cells (Black=1, White=0)
for (let j = 0; j < INITIAL_LENGTH; j++) {
if (rowData[j] === 1) {
ctx.fillStyle = 'black';
ctx.fillRect(j * CELL_WIDTH, yStart, CELL_WIDTH, CELL_HEIGHT);
} else {
// Draw background white if cell is 0
ctx.fillStyle = '#AAA'; // Slightly off-white for the visible background fill
ctx.fillRect(j * CELL_WIDTH, yStart, CELL_WIDTH, CELL_HEIGHT);
}
}
}
}
function animate() {
// Step 1: Update simulation state
updateState();
// Step 2: Draw the current state
draw();
// Step 3: Handle scrolling (if we reach the bottom, scroll up)
const maxScroll = H - ROW_COUNT * CELL_HEIGHT * 0.8; // Reserve space for row number text
if (scrollOffset >= maxScroll) {
scrollOffset = 0;
} else {
// Simulate slow scrolling downward over time, making the pattern appear to flow through the view
// For visual effect, let's make it scroll down slightly and then reset.
/*
if (Math.random() < 0.01) { // Slow drift
scrollOffset += 2;
}
*/
}
requestAnimationFrame(animate);
}
// Initialization sequence
initialize();
animate();
</script>
</body>
</html>
``````html
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Rule 110 Cellular Automaton</title>
<style>
body { margin: 0; overflow: hidden; }
canvas { display: block; }
</style>
</head>
<body>
<canvas id="rule110"></canvas>
<script>
const canvas = document.getElementById('rule110');
const ctx = canvas.getContext('2d');
const width = 800;
const height = 600;
const cellSize = 4;
let rows = 300;
let colCount = Math.floor(width / cellSize);
const ruleTable = [0,1,1,1,0,1,1,0,1,1,0,0,0,1];
canvas.width = width;
canvas.height = height;
let grid = Array.from({length: rows}, () => Array(colCount).fill(0));
grid[0][Math.floor(colCount / 2)] = 1;
function drawGrid() {
ctx.clearRect(0, 0, width, height);
for (let row = 0; row < rows; row++) {
for (let col = 0; col < colCount; col++) {
if (grid[row][col] === 1) {
ctx.fillStyle = 'black';
ctx.fillRect(col * cellSize, row * cellSize, cellSize, cellSize);
}
}
ctx.fillStyle = 'white';
ctx.font = '20px Arial';
ctx.fillText(`Row: ${row}`, 10, (row + 1) * cellSize - 5);
}
}
function evolveGrid() {
const newGrid = grid.slice();
for (let row = 1; row < rows; row++) {
for (let col = 0; col < colCount; col++) {
const left = (col > 0) ? grid[row - 1][col - 1] : 0;
const center = grid[row - 1][col];
const right = (col < colCount - 1) ? grid[row - 1][col + 1] : 0;
const index = left * 4 + center * 2 + right;
newGrid[row][col] = ruleTable[index];
}
}
grid = newGrid.slice(1);
grid.unshift(Array(colCount).fill(0));
}
function animate() {
if (frames % 5 === 0) {
evolveGrid();
drawGrid();
}
frames++;
requestAnimationFrame(animate);
}
let frames = 0;
drawGrid();
requestAnimationFrame(animate);
</script>
</body>
</html>
``````html
<!DOCTYPE html>
<html>
<head>
<title>Rule 110 Cellular Automata</title>
<style>body { background: #000; display: flex; justify-content: center; align-items: center; min-height: 100vh; margin: 0; font-family: monospace; color: #fff;} canvas { border: 1px solid #333; }#info { position: absolute; top: 20px; left: 50%; transform: translateX(-50%); color: #aaa; }</style>
</head>
<body>
<div id="info">Row: 0</div>
<canvas id="caCanvas"></canvas>
<script>
const canvas = document.getElementById('caCanvas');
const ctx = canvas.getContext('2d');
const infoDiv = document.getElementById('info');
let W = 800; // Width
let H_CANVAS = 600; // Visible height
canvas.width = W;
canvas.height = H_CANVAS;
// Grid parameters
const CELL_SIZE = 10;
const GRID_WIDTH = Math.floor(W / CELL_SIZE);
const MAX_HISTORY = 50; // Maximum number of rows to store history
let gridHistory = [];
let scrollOffset = 0;
let rowCount = 0;
// Rule 110 lookup table (L, C, R) -> Output bit. Binary: 01111010
// Index mapping: LCR maps to $4*L + 2*C + R$. The output value is the coefficient of that index in the rule number.
const RULE_MAP = [0, 1, 1, 1, 1, 0, 1, 0]; // Indices 0 through 7
// --- Initialization ---
function initialize() {
gridHistory = [];
rowCount = 0;
scrollOffset = 0;
infoDiv.textContent = `Row: ${rowCount}`;
}
// Sets the initial state (single black cell in the top row)
function setInitialState() {
const newRow = Array(GRID_WIDTH).fill(0);
newRow[Math.floor(GRID_WIDTH / 2)] = 1;
gridHistory.unshift(newRow); // Add to the start (top)
}
// --- Core Logic ---
function computeNextRow() {
const lastRow = gridHistory[0];
if (!lastRow) return null;
const newRow = Array(GRID_WIDTH).fill(0);
for (let i = 1; i < GRID_WIDTH - 1; i++) {
// Pattern: L, C, R
const l = lastRow[i - 1];
const c = lastRow[i];
const r = lastRow[i + 1];
// Calculate index (L*4 + C*2 + R*1)
const patternIndex = (l * 4) + (c * 2) + r;
newRow[i] = RULE_MAP[patternIndex];
}
return newRow;
}
function updateGrid() {
// Calculate the next row
const nextRow = computeNextRow();
if (!nextRow) return false;
// Shift history: Remove oldest, prepend newest
gridHistory.unshift(nextRow);
if (gridHistory.length > MAX_HISTORY) {
gridHistory.pop();
}
rowCount++;
infoDiv.textContent = `Row: ${rowCount}`;
return true;
}
// --- Drawing and Animation ---
function drawGrid() {
ctx.fillStyle = '#000';
ctx.fillRect(0, 0, W, H_CANVAS);
const visibleHistory = gridHistory.slice(0, Math.floor(H_CANVAS / CELL_SIZE));
const startY = scrollOffset;
for (let r = 0; r < visibleHistory.length; r++) {
const rowData = visibleHistory[r];
const yPos = startY + r * CELL_SIZE;
for (let c = 0; c < GRID_WIDTH; c++) {
if (rowData[c] === 1) {
ctx.fillStyle = '#fff'; // Active cell color
ctx.fillRect(c * CELL_SIZE, yPos, CELL_SIZE - 1, CELL_SIZE - 1);
} else {
ctx.fillStyle = '#000'; // Empty space (already handled by fillRect above)
}
}
}
// Handle scrolling logic: If the bottom row is drawn near the canvas edge, reset scroll
if (gridHistory.length >= Math.floor(H_CANVAS / CELL_SIZE)) {
scrollOffset = 0;
} else if (visibleHistory.length === gridHistory.length) {
// Only update offset if we haven't hit the max capacity yet, otherwise standard scrolling applies
const newScroll = Math.min(Math.max(0, scrollOffset - CELL_SIZE), H_CANVAS - visibleHistory.length * CELL_SIZE);
scrollOffset = newScroll;
}
}
function animate() {
// 1. Update the state (compute next row)
const didUpdate = updateGrid();
// If we are at max depth, start scrolling/wrapping logic
if (gridHistory.length >= Math.floor(H_CANVAS / CELL_SIZE)) {
scrollOffset -= CELL_SIZE; // Scroll up
} else if (didUpdate) {
// If we just added a row and haven't hit max depth, keep scroll at 0 for smooth growth visualization
scrollOffset = 0;
}
// 2. Draw the state
drawGrid();
requestAnimationFrame(animate);
}
// --- Execution Start ---
initialize();
setInitialState();
animate```html
<!DOCTYPE html>
<html>
<head>
<style>
body { margin: 0; overflow: hidden; }
#canvas { border: none; }
</style>
</head>
<body>
<canvas id="c" width=300 height=200></canvas>
<script>
var c = document.getElementById('c');
var ctx = c.getContext('2d');
var r = 10, w = 8;
function draw() {
ctx.clearRect(0,0,c.width,c.height);
var s = new Array(c.height-1).fill(0);
for (var i=0; i<=c.height-2; i++) {
var t = new Array(c.width);
for (var j=c.width-1;j>=0;j--) {
if (i==0) {
t[j] = document.random();
} else {
var p = s[j];
var q = s[j+1] || 0;
if (j==c.width-1 && !q) q=0; // edge case
t[j] = r110(p,q);
}
}
s=i;
for (var j=c.width-1;j>=0;j--) {
ctx.fillStyle = t[j]? 'black' : 'white';
ctx.fillRect(j*r,i*r,(r+1)*w,r*w);
}
}
var row = Math.floor(s/c.height*100) + '%';
ctx.font = '16px sans-serif';
ctx.textAlign='left';ctx.textBaseline='top';
ctx.fillText('Row '+Math.floor(s),0,0);
}
function r110(p,q) {
return (p+q+(p*q))&1;
}
var f=0;
setInterval(function(){
draw();
if (++f%20==0 && s>=c.height-2) { // scroll
ctx.clearRect(0,c.height-10+c.height, c.width, 30);
var row = Math.floor(s/c.height*100) + '%';
ctx.font = '16px sans-serif';
ctx.textAlign='left';ctx.textBaseline='top';
ctx.fillText('Row '+Math.floor(s),0,0);
}
},500/6); // 30fps
document.addEventListener("DOMContentLoaded", function(){ draw(); });
</script>
</body>
</html>
``````html
<!DOCTYPE html>
<canvas id="caCanvas"></canvas><script>
const canvas = document.getElementById('caCanvas');
const ctx = canvas.getContext('2d');
let gridRows = []; // Stores the active rows for calculation (L, C, R)
let rowCount = 0; // Total steps/rows calculated
let scrollOffset = 0; // Vertical position of the drawn pattern's top edge
let frameId = null;
// Rule 110 lookup table: Index is LCR binary value. Value is next state.
const RULE_110 = [0, 1, 1, 1, 0, 1, 1, 0];
function calculateNextRow(currentRow) {
const N = currentRow.length;
if (N === 0) return [];
let nextRow = new Array(N + 2).fill(0); // Allow for potential expansion/padding
// Pad the row with assumed '0' boundaries if necessary, though calculation handles this by iterating over valid indices
for (let i = 1; i < N + 1; i++) {
const L = parseInt(currentRow[i - 1]);
const C = parseInt(currentRow[i]);
const R = parseInt(currentRow[i + 1] || 0); // Handle boundary right padding
// Calculate the index (L*4 + C*2 + R) and apply Rule 110
const index = (L << 2) | (C << 1) | R;
nextRow[i] = RULE_110[index];
}
return nextRow.map(b => b === 1 ? 1 : 0);
}
function initialize() {
// Start with a single row of '0's, containing only one '1' in the middle.
const initialLength = 50;
let startRow = new Array(initialLength).fill(0);
startRow[Math.floor(initialLength / 2)] = 1;
gridRows = [startRow];
rowCount = 1;
scrollOffset = 0;
}
function updateSimulation() {
if (gridRows.length === 0) return false;
// 1. Calculate the next row based on the last calculated row
let newRow = calculateNextRow(gridRows[gridRows.length - 1]);
// 2. Store state and check for growth/scroll condition
const currentHeight = gridRows.length * 20; // Assuming 20px per row
const canvasHeight = canvas.clientHeight || (currentHeight + 50); // Ensure enough space initially
if (canvasHeight < currentHeight + 20) {
// Scroll down if the new pattern exceeds visible area
scrollOffset += 180; // Scroll by roughly two rows worth of height
} else {
// If we don't scroll, we just grow downwards.
// (In this implementation, since we are always appending and redrawing from a fixed canvas size,
// the scrolling logic handles the necessary view shift.)
}
gridRows.push(newRow);
rowCount++;
return true;
}
function drawSimulation() {
const CANVAS_W = 800;
const CANVAS_H = Math.max(window.innerHeight, 600);
canvas.width = CANVAS_W;
canvas.height = CANVAS_H;
ctx.fillStyle = '#111';
ctx.fillRect(0, 0, CANVAS_W, CANVAS_H);
const TILE_SIZE = 20; // Size of one cell block
let yOffset = -scrollOffset + (canvas.clientHeight / 5); // Start drawing slightly above the visible top to manage scroll jitter
// Draw grid content and row counter
for (let i = 0; i < gridRows.length; i++) {
const row = gridRows[i];
let xPos = 0;
let yPos = TILE_SIZE * i + yOffset; // Calculate position of the current row
if (yPos >= CANVAS_H || yPos <= -TILE_SIZE * 5) {
// Skip drawing rows that are entirely outside the visible canvas area
continue;
}
for (let j = 0; j < row.length; j++) {
const state = row[j];
if (state === 1) {
ctx.fillStyle = '#333'; // Black cell
ctx.fillRect(xPos * TILE_SIZE, yPos, TILE_SIZE, TILE_SIZE);
}
xPos++;
}
}
// Draw Row Number Counter
ctx.fillStyle = 'white';
ctx.font = '18px monospace';
ctx.fillText(`Row: ${rowCount - 1}`, 10, 25);
}
function animate() {
if (!updateSimulation()) {
// If update fails (e.g., memory issue), stop animation
cancelAnimationFrame(frameId);
return;
}
drawSimulation();
// Schedule the next frame request
frameId = window.requestAnimationFrame(animate);
}
window.onload = () => {
initialize();
animate();
};
</script>
``````html
<!DOCTYPE html>
<html><body style="margin:0;overflow:hidden;">
<canvas id=c></canvas>
<script>
const c=document.getElementById('c'),ctx=c.getContext('2d');
const w=c.width=800,h=c.height=600;
let r=Array(3),x=0,y=0,speed=4,rows=1,currentRow=1;
for(let i=0;i<3;i++)r[i]=Array(w).fill(0);
r[1][w/2|0]=1;
function draw() {
ctx.fillStyle='#fff';ctx.fillRect(x,y,w,h);
for(let y=0;y<r.length-1;y++) {
let ry=r[y],ry1=r[y+1];
for(let x=0;x<ry.length;x++) {
if(ry[x]) {
const i=x-1,j=x,k=x+1;
const left=jy=i>=0?ry[i]||0:0;
const me=jy=ry[x];
const right=kx=k<ry.length?ry[k]:0;
const b=(left<<2)|((me&2)>>1)|(right>>1);
ry1[x]=b^5;
}
}
}
ctx.fillStyle='#000';
for(let y=0;y<r.length-1;y++) {
let row=r[y],y1=y*sy;row.forEach((v,x)=>{if(v){ctx.fillRect(x*2+sx,(h-(r.length-y)*sh)+cy,1,sh);}});
}
if(currentRow<=rows) {
ctx.fillStyle='#6';ctx.font='30px monospace';ctx.fillText('Rule 110',10,50);
ctx.fillText(`Row: ${currentRow}`.padStart(20),10,h-10);
} else {
x=0;y++;if(y>=r.length) reset();
}
}
let sy=h/(rows+3),sh=sy/4,sx=5,cy=sy*2;
function reset() {
r=[Array(w).fill(0)];x=y=0;currentRow=1;
r[0][w/2|0]=1;
}
function animate(timestamp) {
if(currentRow>rows)reset();
const frames=currentRow%speed==0?4:2;
for(let i=0;i<frames;i++) currentRow++;
draw();
requestAnimationFrame(animate);
}
requestAnimationFrame(animate);
</script>
</body></html>
``````html
<!DOCTYPE html><html><head><meta charset="utf-8"><title>Rule 110</title><style>canvas{position:relative}#r{text-align:center;display:block;margin:5px}</style></head><body>
<canvas id=c width=700 height=496></canvas><div id=r>Row 0</div><script>
const c=document.getElementById('c'),ctx=c.getContext('2d');
let cols=128,cellSize=3,row=0,cells=[],maxRows=c.height;
function init(){
cells=[new Array(cols).fill(0)];
cells[0][Math.floor(cols/2)]=1;
}
init();
function rule110(currentRow){
const nextRow=new Array(cols).fill(0);
for(let i=0;i<cols;i++){
let left=currentRow[(i-1+cols)%cols];
let center=currentRow[i];
let right=currentRow[(i+1)%cols];
let state=left*4 + center*2 + right;
nextRow[i]=state==3?1:0;
}
return nextRow;
}
function draw(){
ctx.fillStyle='white';
ctx.fillRect(0, row%maxRows, c.width,c.height/maxRows);
for(let y=row;y>=0 && y>row -c.height/cellSize;y--){
const cy=(y % maxRows)*cellSize;
ctx.fillStyle='black';
cells[y].forEach((val,x)=>{
if(val)ctx.fillRect(x*cellSize, cy, cellSize-1,cellSize-1);
});
}
}
function animate(){
requestAnimationFrame(animate);
draw();
if(row % 3==0){
setTimeout(()=>{
if(cells.length>=maxRows && cells.length>0){
cells.shift();
document.getElementById('r').textContent=`Row ${cells.length}`;
}
const nextRow=rule110(cells[cells.length-1]);
cells.push(nextRow);
row++;
if(cells.length==1)document.getElementById('r').textContent=`Row 1`;
else document.getElementById('r').textContent=`Row ${cells.length - (row >= maxRows ? 0 : 0)}`
},50);
}
}
animate();
</script></body></html>
``````html
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Rule 110 Cellular Automaton</title>
<style>
body { margin: 0; }
canvas { border: solid black 2px; background: white; display: block; margin: auto; }
</style>
</head>
<body>
<canvas id="ca" width="500" height="500"></canvas>
<script>
const ca = document.getElementById("ca");
const ctx = ca.getContext("2d");
let running = false;
let rowCountdown = 1;
let frameCountdown = 7;
function draw() {
if (!running) return;
requestAnimationFrame(draw);
const w = ca.width / 3, h = ca.height / 500;
ctx.clearRect(0, 0, ca.width, ca.height);
ctx.fillStyle = "black";
for (let x = 1; x < w - 1; ++x) {
if (!frameCountdown--) {
--rowCountdown; frameCountdown = 7; }
const y = Math.floor(ca.height / h * rowCountdown);
ctx.fillRect(x*3,y,h,h);
} if (++rowCountdown > ca.height/h) { running = false; start(); }
}
function rule110(current) {
return ((current[0] + current[2]) % 2 == 1 && current[1] == 0 ? 1 : 0);
}
function start() {
if (running) return; running = true; draw();
ctx.fillRect(w, ca.height-h, h, h);
for (let x = 0; x < w - 2; ++x)
ctx.fillRect(3+x*3,ca.height-h-h,h,h);
}
start();
</script>
</body>
</html>
```<think>
Okay, the user wants me to create a self-contained HTML file that draws the Rule 110 cellular automaton on a canvas. Let me start by recalling what Rule 110 entails. The rule defines the next state of a cell based on its current state and the two adjacent cells. The rule number 110 in binary is 0b1101110, which corresponds to the decimal 110. The lookup table for Rule 110 is:
The binary 110 is 0b01101110, so the rules are as follows:
For each triplet of three cells (left, current, right), the next state is determined by:
111 -> 0
110 -> 1
101 -> 1
100 -> 0
011 -> 1
010 -> 1
001 -> 1
000 -> 0
Wait, let me double-check that. The decimal 110 in binary with 8 bits is 01101110. The bits are read from left to right as the possible combinations. The order of the combinations is from 111 to 000. So the mapping is:
111 → 0 (0)
110 → 1 (1)
101 → 1 (1)
100 → 0 (2)
011 → 1 (3)
010 → 1 (4)
001 → 1 (5)
000 → 0 (6)
So the next state is the bit in the rule's position corresponding to the triplet.
The task is to set up a canvas, start with a single cell in the top row, and compute each subsequent row. Each row should be drawn per few frames, probably using requestAnimationFrame for smooth animation. Also, when the pattern reaches the bottom of the canvas, it should scroll up so it keeps running indefinitely. Need to display the row number as well.
First, I need to structure the HTML file with a canvas element and some JavaScript to handle the animation. The restrictions are that it must be self-contained, no external libraries, and under 7000 characters. Let me think about the steps needed.
Starting with the basic structure:
<!DOCTYPE html>
<html>
<body>
<canvas id="ca"></canvas>
<div id="row">Row: 0</div>
<script>
// JavaScript code here
</script>
</body>
</html>
The canvas needs to be initialized with a certain width and height. Let's decide on some parameters. Since Rule 110 needs to expand, the width of the canvas should be at least enough to show the growth. Maybe set the width to, say, 600px and height to 300px, but these can be adjusted later.
The canvas context will be 2D. The initial row starts with a single black cell in the middle. So the initial state is an array where the center element is 1, others are 0.
The animation loop will use requestAnimationFrame to draw each step. Each step is a row. The drawing should be done in a way that each row is drawn below the previous, but when the bottom is reached, the entire canvas shifts upward.
Wait, how to handle scrolling? One approach is to have a buffer that's larger than the visible area, or to keep track of the current row and scroll the canvas when needed. Alternatively, when drawing each new row, after a certain number of rows, we can shift the canvas content upwards by one row, leaving space at the bottom. Hmm, perhaps the latter is easier.
Alternatively, we can manage an array representing the current row and the next row. Each time a new row is generated, we draw it to the canvas one row below, and once the drawing reaches the bottom, we start over but shifting the existing rows up. But that might be complicated.
Alternatively, have the canvas buffer that is as large as possible, but since the animation needs to continue indefinitely, maybe we can just keep adding rows below and when the bottom is reached, instead of resetting, but the user wants it to keep running, so scrolling up makes sense.
Hmm, so when the current row reaches the bottom of the canvas (height), we need to scroll the canvas up by one row (so that the oldest row is removed, and new rows are added at the bottom). To do that, each time we draw a new row, after a certain number of rows, we can shift the existing canvas content upwards by the row height (since each row is one pixel in height?), but perhaps the rows are drawn with a certain height. Wait, the canvas uses pixels, so each row is a row of pixels. So the height of the canvas is, say, 300 pixels, so each row is one pixel tall. Wait, but that would make the rows very thin, so maybe each row is several pixels.
Wait, the user said "draw one new row per few frames". Maybe the rows are drawn every few animation frames, but the actual row height can be one pixel. However, for visualization, it might be better to have each row take, say, 5 pixels in height so they are visible. Let me think: the canvas has a certain height, say 300px, and each row takes 5px. Then, after 60 rows, the pattern will reach the bottom. Then, scrolling begins.
Alternatively, the rows are drawn as single pixels, so each row is one pixel. Then, when the current row reaches the bottom (say 300px), we start drawing new rows at the top again, but that would erase previous rows. Alternatively, the idea is that when the bottom is reached, we shift the entire canvas content up by one row (one pixel) each time a new row is drawn beyond the bottom. This way, the oldest row is removed, and new rows are added at the bottom, creating a scrolling effect upwards.
To implement this, when the current row count (let's call it 'row') exceeds the canvas height (canvas.height), then each new row is drawn starting from row - canvas.height, and we can shift the entire canvas content up by one row.
Wait, perhaps an easier way is to use a buffer array that's as large as needed, and each time you draw a new row, you shift all pixels up except for the new row. But that might be too slow for large buffers. Alternatively, use the canvas's drawing context to shift the content.
Alternatively, the canvas can be redrawn each frame, but that might be inefficient for large heights. Hmm, perhaps the best approach is to have the canvas height represent the visible area, and the actual rows are stored in an array. Each time a new row is generated, it is appended to the array. Once the array length exceeds the canvas height, when drawing, we start from the last 'canvas height' rows. However, this might require redrawing the entire visible area each time, which could be feasible if the canvas isn't too large.
Alternatively, use the canvas's translate function to shift the content. But shifting the coordinate system might be a way. Let me think:
Suppose the canvas has a height of H. The rows are drawn starting at y = currentY. Each time a new row is drawn, currentY increments by 1. When currentY reaches H, then we can set currentY to 0 and start over, but that would reset the pattern, which isn't desired. Instead, we need to shift the existing drawing.
Wait, here's an idea: the drawing is done on the canvas, but every time the current row (y) exceeds the canvas height, we can copy the current canvas content up by one row (using context.drawImage to shift the existing image up by one row), and then draw the new row at the bottom. This way, the oldest row is erased, and the new row is added below, creating a continuous scroll upwards.
This approach would involve:
- Keeping track of the current row count (rowNumber).
- After each step, the new row is drawn at y = rowNumber.
- When rowNumber reaches the canvas height (H), then we need to shift the entire canvas content up by 1 pixel, so that rows 1 to H-1 are now at 0 to H-2, and then the new row (row H) is drawn at H-1 (or similar). Wait, perhaps the steps are:
When rowNumber reaches H:
- Copy the canvas content from y=1 to y=H-1 into y=0 to y=H-2 using the drawImage method with a source rectangle.
- The new row is then drawn at y = H-1.
- Then, rowNumber increments, so next row is at H, which is again beyond, so the next step will shift again.
Wait, but this would require that each time when rowNumber exceeds the height, we shift the content. So, the key is, whenever rowNumber > H, we shift up before drawing the new row.
Alternatively, when rowNumber reaches H, then each subsequent row is drawn at y = rowNumber - H_start, where H_start is the initial starting point. Hmm, perhaps the shifting approach is better.
So, the steps in the animation loop would be:
1. Generate the next row based on the previous row's state.
2. If the current row (rowNumber) is less than the canvas height, draw the new row at y=rowNumber.
3. If rowNumber exceeds the canvas height, shift the canvas content up by 1 pixel (so the oldest row is removed), and draw the new row at the bottom (y = canvas.height -1).
4. Update the rowNumber.
But to shift the canvas up by one pixel, we can use:
ctx.drawImage(canvas, 0, 1, canvas.width, canvas.height -1, 0, 0, canvas.width, canvas.height -1);
Wait, maybe using ctx.drawImage to copy the content from the current canvas to itself, but shifted up by one row. For example:
ctx.drawImage(ctx.canvas, 0, 1, ctx.canvas.width, ctx.canvas.height - 1, 0, 0, ctx.canvas.width, ctx.canvas.height - 1);
Then, the new row is drawn at the bottom (current row is H, so y = H -1 if the canvas height is H).
Wait, let me think of the canvas as having a height of H. When rowNumber reaches H, the next row would be H+1. To accommodate that, we need to shift the existing H rows up by 1, so that:
- The previous rows 0 to H-1 are now at -1 to H-2 (but that's not possible). Maybe:
The current canvas has rows from 0 to H-1. The next row is H. To shift up, we can copy the rows 0 to H-1 to rows 1 to H, but that would require overwriting. Alternatively, perhaps:
The drawImage approach would copy the current image (the entire canvas) from y=1 down to y=0, effectively moving everything up by one pixel, but losing the top row. Then, the new row is drawn at the bottom (y=H-1). This way, each time the rowNumber exceeds H, the canvas is shifted up, and the new row is added at the bottom.
So the steps in code would be:
if (rowNumber > canvasHeight) {
// Shift existing content up by 1 row
ctx.drawImage(canvas, 0, 1, canvas.width, canvas.height -1, 0, 0, canvas.width, canvas.height -1);
// Now draw the new row at the bottom
ctx.fillStyle = 'black';
for (let x = 0; x < width; x++) {
if (newRow[x] === 1) {
ctx.fillRect(x, canvas.height - 1, 1, 1);
}
}
rowNumber++;
} else {
// draw normally at rowNumber
...
}
Wait, but the rowNumber is tracking how many rows have been drawn, so when it exceeds H, we need to shift and draw the new row at the bottom. But the rowNumber increments regardless.
But in this approach, after shifting, the new row is drawn at the bottom (y=canvas.height-1), and the next row would be y=canvas.height, but since we are using rowNumber to track, after shifting, the next row is also shifted, so the rowNumber is effectively modulo the canvas height? Not exactly, but the visual effect is that the pattern continues scrolling upwards.
However, the problem is that after shifting, the previous rows are shifted up, so the new row is at the bottom, and the following rows are drawn there. So the rowNumber is not used for the y-coordinate anymore once we have started scrolling. Hmm, perhaps need to adjust how the y-coordinate is calculated.
Alternatively, once we reach the bottom, the y-coordinate for new rows is always at the bottom, but the rowNumber keeps increasing. The y-coordinate can be set as (rowNumber - currentScroll) % H or something, but that might complicate the drawing.
Alternatively, track the currentScroll variable. For example:
var scroll = 0;
Each time rowNumber exceeds H, we increment scroll by 1. The current effective row on the canvas is (rowNumber - scroll) % H. Wait, perhaps not exactly.
Alternatively, the rows are stored in an array, and when drawing, we only draw the last H rows. But storing the rows might take memory, but for a canvas of say 300 rows, each row being an array of say 600 elements (each a 0 or 1), that's manageable.
Wait, perhaps the most straightforward way is to store an array of previous rows, and each new row is added to this array. The canvas is drawn by taking the last 'canvasHeight' rows from the array. But this requires redrawing the entire visible area each time, which could be manageable as long as the array isn't too big.
Let me think of the steps:
- Initialize an array rows = [initialRow], where initialRow is the first row with a single 1 in the center.
- The canvas height is set to a desired value, say 300.
- Each animation frame, compute the next row.
- Add this new row to the rows array.
- The displayed rows are rows.slice(-canvasHeight) if rows.length > canvasHeight, else all rows.
- Each frame, redraw the canvas by iterating over the displayed rows (each row in the array, up to the last 'canvasHeight' rows), and drawing each cell as a pixel.
But this might be slow if the array gets very long, but since the animation is frame-based and the canvas isn't too big (e.g., 600x300 pixels), maybe it's manageable.
Alternatively, the array can be kept up to the canvas height to prevent it from growing indefinitely. Once the array's length exceeds the canvas height, we can keep only the last 'canvas height' rows. That way, when scrolling, we only keep the rows needed to display. This reduces memory usage.
Wait, but when scrolling, the oldest rows are removed, so the array's length stays at canvas height. So:
rows = rows.slice(-canvasHeight).concat( [newRow] );
Wait, no, that would not work. Each time a new row is added, the array's length increases by one. So after N rows, it's N elements. To keep only the last H rows (canvas height), we can do rows = rows.slice(-canvasHeight) before adding the new row? Wait, no. Wait, perhaps after adding the new row:
rows.push(newRow);
if (rows.length > canvasHeight) {
rows.shift();
}
Wait, but that would keep the array length at maximum canvasHeight, so the first elements are being popped off. But that way, the rows array only contains the last 'canvasHeight' rows, so when drawing, we can just loop through them and draw each row at their respective y positions (from 0 to H-1). But the actual row number (the count) would still be increasing, but the displayed rows are just the last H rows. However, the row number displayed (the text) should reflect the actual row count, not the displayed rows. Hmm, perhaps this is manageable.
Wait, let me structure this approach:
Variables:
- rows: array storing the rows. Initially, rows[0] is the first row (single cell). Each row is an array of 0s and 1s.
- The canvas has width 'width', height 'height'.
- The animation loop does:
1. Compute next row based on last row in 'rows'.
2. Add the new row to 'rows'.
3. If rows.length > canvasHeight (given by height), remove the first element (so rows stays at height length).
4. Redraw the canvas by looping over rows, and each row is drawn at y = index (the array's index in rows).
5. Display the row count as the length of rows (before steps 2 and 3?), but since after adding the new row, the row count is rows.length, but if rows were shifted, but the actual row count is (previous rows.length) +1 (since we added a new row). Wait, perhaps the row count is tracked in a separate variable, say 'generation', which is incremented each time.
This way, rows could be kept at maximum height elements, but we still track the generation number to display the row count.
This approach would allow the canvas to scroll automatically because when rows.length exceeds the height, the first row is removed, so the display shifts up each time a new row is added beyond the height. The new row is added to the end, so the displayed rows are the last 'height' rows, giving the illusion of upward scrolling.
This seems manageable. So let's outline variables:
Let's decide on the canvas dimensions. Let's pick a width that's sufficient to show the expansion. Let's say the canvas is 600 pixels wide and 300 tall. The width of the array for each row will be 600.
Wait, but handling arrays of 600 elements each for rows may be manageable. For 300 rows, that's 300*600 = 180,000 elements, which is acceptable.
Now, the steps in code:
Initialize:
const canvas = document.getElementById('canvas');
const ctx = canvas.getContext('2d');
canvas.width = 600;
canvas.height = 300;
let rows = []; // array of rows
let generation = 0; // tracks the current row number
const width = 600;
const height = 300;
// The initial row has a single cell in the middle (position width / 2)
const initialRow = new Array(width).fill(0);
const mid = Math.floor(width / 2);
initialRow[mid] = 1;
rows.push(initialRow);
// Display generation = 1, but generation starts at 0? Maybe generation is the length of rows?
Wait, let's see:
At initialization, rows has 1 row, so generation is 1. But if generation is initialized to 1, then each time a new row is added, generation increments.
Wait, perhaps generation is rows.length.
But in the code above, after pushing the initial row, rows.length is 1, so generation would be 1.
So in the animation loop, before adding a new row:
generation = rows.length;
Then, when adding a new row, generation increments by 1.
So, in code:
function animate() {
requestAnimationFrame(animate);
// compute next row
const currentRow = rows[rows.length -1];
const newRow = new Array(width).fill(0);
for (let x = 0; x < width; x++) {
// compute the cell based on the current row's cells x-1, x, x+1 (if available)
let sum = 0;
// Here, the rules for the next row's cell at x depend on the current row's x-1, x, x+1.
// For example, if it's a 1D cellular automaton with rule 30: the next cell is based on the three cells above it (left, current, right).
// Wait, the problem here is that the user didn't specify which cellular automaton to use. Wait a second, the original question says:
Original question: "Create..." but didn't specify the rules. Wait, hold on, the user hasn't provided any specifics about the cellular automaton. Wait, this is a problem. Wait, the user just said "create" but didn't specify the rules. Wait, this is a mistake in the question. Wait, let me check the user's input again.
Wait, the user wrote:
"Create<!doctype html><html><head><meta charset="utf-8"><title>Rule 110</title><style>html,body{margin:0;height:100%;overflow:hidden;background:#f5f5f2;color:#111;font:14px system-ui,sans-serif}canvas{display:block;width:100vw;height:100vh;image-rendering:pixelated}#r{position:fixed;top:10px;left:10px;background:#ffffffe6;padding:6px 9px;border:1px solid #bbb}</style></head><body><canvas id="c"></canvas><div id="r">row 0</div><script>
const c=document.getElementById("c"),x=c.getContext("2d"),r=document.getElementById("r");
let w,h,cell,cols,rows,a,b,img,row,seed=0,frames=0;
function size(){
let d=devicePixelRatio||1;
c.width=innerWidth*d;c.height=innerHeight*d;
x.setTransform(d,0,0,d,0,0);
cell=Math.max(2,Math.floor(innerWidth/220));
cols=Math.floor(innerWidth/cell);rows=Math.floor(innerHeight/cell);
restart()
}
function restart(){
a=new Uint8Array(cols);b=new Uint8Array(cols);
a[cols>>1]=1;row=0;seed++;
x.fillStyle="#f5f5f2";x.fillRect(0,0,innerWidth,innerHeight);
draw(a,0);r.textContent="row 0";
}
function next(){
for(let i=0;i<cols;i++){
let l=a[(i+cols-1)%cols],m=a[i],n=a[(i+1)%cols],v=(l<<2)|(m<<1)|n;
b[i]=v==6||v==5||v==3||v==2||v==1
}
let t=a;a=b;b=t;row++;
if(row>=rows){
img=x.getImageData(0,cell,innerWidth,innerHeight-cell);
x.putImageData(img,0,0);
x.fillStyle="#f5f5f2";x.fillRect(0,(rows-1)*cell,innerWidth,cell);
draw(a,rows-1)
}else draw(a,row);
r.textContent="row "+row;
if(row>100000)restart()
}
function draw(arr,y){
x.fillStyle="#111";
for(let i=0;i<cols;i++)if(arr[i])x.fillRect(i*cell,y*cell,cell,cell)
}
function tick(){
frames++;
if(frames%3==0)next();
requestAnimationFrame(tick)
}
addEventListener("resize",size);
size();requestAnimationFrame(tick);
</script></body></html><!DOCTYPE html>
<html><head><meta charset="utf-8">
<title>Rule 110</title>
<style>
html,body{margin:0;padding:0;background:#05060a;overflow:hidden;height:100%;width:100%}
canvas{display:block}
#hud{position:fixed;top:8px;left:10px;font:13px monospace;color:#7ee787;text-shadow:0 0 4px #000;pointer-events:none;user-select:none}
</style></head>
<body>
<canvas id="c"></canvas>
<div id="hud">row 0</div>
<script>
var cv=document.getElementById('c'),ctx=cv.getContext('2d'),hud=document.getElementById('hud');
var cell=6,cols,W,H,row,y,rowNum,liveColor,deadColor,framesPerRow=3,fc=0;
var maxRows;
function resize(){
W=window.innerWidth;H=window.innerHeight;
cv.width=W;cv.height=H;
cols=Math.max(3,Math.floor(W/cell));
}
function table(l,c,r){
var i=(l<<2)|(c<<1)|r;
var t=[0,1,1,1,0,1,1,0];
return t[i];
}
function newColors(){
var h=Math.floor(Math.random()*360);
liveColor='hsl('+h+',80%,60%)';
deadColor='#05060a';
}
function initFresh(random){
resize();
ctx.fillStyle=deadColor;
ctx.fillRect(0,0,W,H);
row=new Array(cols).fill(0);
if(random){
for(var i=0;i<cols;i++) row[i]=Math.random()<0.35?1:0;
var any=false;
for(var i=0;i<cols;i++) if(row[i]){any=true;break;}
if(!any) row[Math.floor(cols/2)]=1;
} else {
row[Math.floor(cols/2)]=1;
}
y=0;
rowNum=0;
maxRows=800+Math.floor(Math.random()*800);
drawRow(row,y);
rowNum++;
y+=cell;
}
function drawRow(r,py){
for(var x=0;x<cols;x++){
ctx.fillStyle=r[x]?liveColor:deadColor;
ctx.fillRect(x*cell,py,cell,cell);
}
}
function nextRow(r){
var n=new Array(cols);
for(var x=0;x<cols;x++){
var l=r[(x-1+cols)%cols];
var c=r[x];
var rr=r[(x+1)%cols];
n[x]=table(l,c,rr);
}
return n;
}
function step(){
if(rowNum>=maxRows){
newColors();
initFresh(true);
hud.textContent='row 0';
return;
}
if(y+cell>H){
var img=ctx.getImageData(0,cell,W,H-cell);
ctx.putImageData(img,0,0);
ctx.fillStyle=deadColor;
ctx.fillRect(0,H-cell,W,cell);
y=H-cell;
}
row=nextRow(row);
drawRow(row,y);
rowNum++;
y+=cell;
hud.textContent='row '+rowNum;
}
function loop(){
fc++;
if(fc>=framesPerRow){
fc=0;
step();
}
requestAnimationFrame(loop);
}
newColors();
initFresh(false);
window.addEventListener('resize',function(){
newColors();
initFresh(true);
});
requestAnimationFrame(loop);
</script>
</body></html><!DOCTYPE html>
<html>
<head><meta charset="utf-8"><meta name="viewport" content="width=device-width"><style>body{margin:0;background:#000;display:flex;justify-content:center;align-items:center;height:100vh}canvas{border:1px solid #333}#i{position:absolute;top:10px;left:10px;color:#fff;font-family:monospace;font-size:12px}</style></head>
<body>
<canvas id="c"></canvas>
<div id="i">Row: <span id="r">0</span></div>
<script>
const c=document.getElementById('c'),ctx=c.getContext('2d');
c.width=600;c.height=600;
const sz=2;const w=Math.floor(c.width/sz),h=Math.floor(c.height/sz);
const rule=110;let current=new Uint8Array(w),scroll=0,row=0;
current[w>>1]=1;
function step(){const next=new Uint8Array(w);for(let x=0;x<w;x++){const l=current[(x-1+w)%w],c=current[x],r=current[(x+1)%w];const idx=(l<<2)|(c<<1)|r;next[x]=(rule>>(idx))&1;}
current=next;row++;}
function f(){for(let i=0;i<3;i++)step();if(scroll>h-1){ctx.clearRect(0,0,c.width,c.height);scroll=0;row=0;}
ctx.fillStyle='#fff';for(let x=0;x<w;x++){if(current[x]){ctx.fillRect(x*sz,scroll*sz,sz,sz);}}
scroll++;document.getElementById('r').textContent=row;requestAnimationFrame(f);}
f();
</script>
</body>
</html>| Model | Blind score | Latency | Status |
|---|---|---|---|
| qwen3:8b | — | — | harness |
| qwen3:14b | — | 34.1 s | OK |
| gemma4:26b | — | — | harness |
| mistral-small:24b | — | 169.0 s | OK |
| qwen3-coder:30b | — | 39.6 s | OK |
| llama3.1:8b | — | 89.7 s | OK |
| qwen3.5:9b | — | 54.8 s | OK |
| deepseek-r1:14b | — | 62.5 s | OK |
| deepseek-r1:32b | — | 41.6 s | OK |
| command-r:35b | — | 79.1 s | OK |
| qwq:32b | — | 142.2 s | OK |